Importance: Low to Medium. While not a primary focus, Time and Work concepts can appear in Data Interpretation caselets. These problems typically involve comparing the efficiency of different individuals or teams in completing a task, such as drafting documents, reviewing cases, or processing applications. The key is understanding efficiency and combined work rates.
How it's tested: Calculating combined time taken by multiple entities; finding efficiency of an individual from group work; problems involving pipes and cisterns (similar logic to Time & Work).
Time and Work problems deal with the rate at which work is done. The core idea is that the total work is constant, and it can be completed by varying the number of workers or their efficiency.
Efficiency = Work / Time (Work done per unit of time)Time = Work / EfficiencyOften, 'Total Work' is assumed as '1 unit' or a convenient LCM.
1/N of the total work.(1/x + 1/y) work per day.1 / (1/x + 1/y) = (x*y) / (x+y) days.Efficiency = Total Work / Time Taken.M1*D1*H1/W1 = M2*D2*H2/W2 (where M=Men, D=Days, H=Hours/day, W=Work). Useful for problems comparing different groups.Passage Context: An experienced lawyer can draft a legal brief in 20 hours. A junior lawyer, working alone, takes 30 hours to draft the same brief.
Question: "If they both work together on the brief, how many hours will it take them to complete it?"
Detailed Solution (using LCM Method):
1. Total Work: Assume Total Work = LCM of 20 and 30 = 60 units (e.g., 60 pages to draft).
2. Calculate Individual Efficiencies:
Experienced Lawyer's Efficiency = 60 units / 20 hours = 3 units/hour.
Junior Lawyer's Efficiency = 60 units / 30 hours = 2 units/hour.
3. Calculate Combined Efficiency:
Combined Efficiency = 3 units/hour + 2 units/hour = 5 units/hour.
4. Time Taken Together:
Time = Total Work / Combined Efficiency = 60 units / 5 units/hour = 12 hours.
Answer: It will take them 12 hours to complete the brief together.
Passage Context: A large water tank that supplies water to a law college has two inlet pipes, A and B, and one outlet pipe, C. Pipe A can fill the tank in 10 hours. Pipe B can fill it in 15 hours. Pipe C can empty the full tank in 12 hours.
Question: "If all three pipes are opened simultaneously, how long will it take to fill the empty tank?"
Detailed Solution (using LCM Method):
1. Total Work (Capacity of Tank): LCM of 10, 15, and 12 = 60 units (e.g., 60 liters).
2. Calculate Individual Rates (Efficiency):
Pipe A (filling) = 60 units / 10 hours = +6 units/hour.
Pipe B (filling) = 60 units / 15 hours = +4 units/hour.
Pipe C (emptying) = 60 units / 12 hours = -5 units/hour (negative because it's emptying).
3. Calculate Combined Rate (Net Efficiency):
Combined Rate = A's rate + B's rate + C's rate = 6 + 4 - 5 = 5 units/hour.
4. Time Taken Together:
Time = Total Work / Combined Rate = 60 units / 5 units/hour = 12 hours.
Answer: It will take 12 hours to fill the tank if all three pipes are opened simultaneously.
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